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Arlecino [84]
3 years ago
10

I need help with my homework please?Anna can buy 3 sweatshirts for a total of $45. How much would it cost if she were to buy 5 s

weatshirts at the same price?
Mathematics
1 answer:
Reptile [31]3 years ago
6 0
Nine dollars per sweatshirt (5) in total 45
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Evaluate the expression 2b to the third power+ 5 when b=5
Andrej [43]

Answer:

1005

Step-by-step explanation:

10 to the third power + 5 =

1000 + 5 =

1005

Hope that helps!

7 0
3 years ago
Graph the inequality. Match the graph to the correct inequality below.
Marina CMI [18]

Answer:

D. x > -3

Step-by-step explanation:

open circle means its either < or > sign. arrow is pointing right which is greater than the number.

3 0
3 years ago
3. Which number is closest to zero on<br> the number line?<br> A -3/8<br> B 3/4<br> C 0.3<br> D 0.50
insens350 [35]

Answer:

0.3

Step-by-step explanation:

A. .375

B. .75

C. .3

D. .5

6 0
3 years ago
Read 2 more answers
Ben and irie made a secret code. they wrote some numbers of the code so they could remember the pattern. what should the next nu
stiks02 [169]
Well what was the pattern they had 

4 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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