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mart [117]
3 years ago
14

3 out of every 5 picks are orange. If 12 picks are orange, how many picks are there in all?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0

Answer:

the are 15 orange ones

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In Aunt Melly's attics there are also spiders and ants, the total of 136 legs and 20 heads. If a spider has 8 legs and an ant ha
anzhelika [568]

Answer:

Spiders=8

Ants=12

Step-by-step explanation:

Spider(s)=8 legs

Ants(a)=6 legs

Total legs=136

Total heads=20

8s+6a=136 (1)

s+a=20 (2)

From (2)

s=20-a

Substitute 20-a into (1)

8s+6a=136

8(20-a)+6a=136

160-8a+6a=136

160-2a=136

-2a=136-160

-2a=-24

a= -24/-2

a=12

Substitute a=12 into (2)

s+a=20

s+12=20

s=20-12

s=8

3 0
4 years ago
The diagonals of a square are 4 meters long. The side of this square is equal to the diagonal of a second square. Find the side
jok3333 [9.3K]
Check the picture below.

since the second figure is also a square, then the sides touching the diagonals have to be all equal, and that'd only happen if those sides bisects the larger square's diagonal.

3 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

6 0
1 year ago
Three roots of the polynomial equation x4 - 4x3 - 2x2 + 12x + 9 = 0 are 3, -1 and -1. Explain why the fourth root must be a real
LiRa [457]
Descares Theorem says that the number of roots of a polynomial is equal to its highest exponent, and the roots could be real and/or imaginary (complex).

However is their is one complex root (a + i.b), it's conjugate is also
a root (a-i.b).

In the equation x⁴ - 4x³ - 2x² + 12x + 9 = 0, we have already 3 roots, then the 4rth cannot be a complex one since we don't have a fifth for its conjugate.

3 0
3 years ago
What is the missing number
Anna35 [415]

Answer:

I got 235, which works in perfectly into the problem...

Step-by-step explanation:

7 0
3 years ago
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