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Lyrx [107]
4 years ago
12

Asphere and a cylinder have the same radius and height. The volume of the cylinder is 64 m3.

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
8 0

Answer:

46

i just took it and i got it right so...

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Please answer asap with an explanation
Sati [7]

Answer:

The area of the given figure is 66.5\ cm^2.

Step-by-step explanation:

To find out the area we should have to redraw the figure having nomenclature ABCDE and join BD. Thus we have a rectangle ABDE and a triangle BCD.

The new figure is in the attachment.

Given,

Length of AE = 7 cm

Length of DE = 8 cm

Length of CF = 11 cm

Solution,

Area of rectangle ABDE = length\times breadth=length\ of AE\timeslength\ of DE

Area of ABDE = 7\times8=56\ cm^2

Now for triangle BCD,

Length of BD = length of AE = 7 cm

Length of GF = Length of DE = 8 cm

∴ Length of CG = Length of CF-Length of GF = 11-8=3\ cm

Area of triangle BCD = \frac{1}{2}\times base\times height}=\frac{1}{2}\times length\ of\ BD\times length\ of\ GF

Area of BCD =  \frac{1}{2}\times7\times3=\frac{21}{2}=10.5\ cm^2

Area of ABCDE = Area of ABDE + Area of BCD = 56+10.5=66.5\ cm^2

Thus the area of the given figure is 66.5\ cm^2.

3 0
4 years ago
3.5+2=2x-10help me HELP ME JIGGABOOS
Genrish500 [490]
3.5 + 2 = 2x - 10
5.5 = 2x -10
+10 +10
—————————
15.5 = 2x
—— ——
2 2

7.75 = x

7.75 is the answer
5 0
1 year ago
Work backward to find the value of the variable in the equation below.
Nikitich [7]

Answer:

there is no equation

Step-by-step explanation:

6 0
4 years ago
Serra rode 15 mi in 1.5 hr. Phaelon rode 38 mi in 3.5 h. Justice rode 22 mi in 2.25 hr. Who had the fastest average speed?
Tamiku [17]
Phaelon had the fastest average speed. I hope this helps :)

3 0
4 years ago
Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th
soldier1979 [14.2K]

Answer:

\frac{9}{20} students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}

\text{Students who play a sport and a part of the drama club}=\frac{9}{20}

Therefore, \frac{9}{20} students play sport and part of the drama club.

5 0
3 years ago
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