Question

Please help me :) once again

Answer 1

Answer:

About 11.31 cm

Step-by-step explanation:

If one of the legs of a right iscosceles triangle is 8, then the length of the other one must also be 8. Therefore, by the Pythagorean Theorem:

$h=\sqrt{8^2+8^2}=\sqrt{64+64}=\sqrt{128}\approx11.31$

Hope this helps!

Answer 2

Answer:

11.31 cm

Solution,

Hypotenuse=?

Perpendicular=8 cm

Base=8cm

Now,

Using Pythagoras theorem,

h^2=p^2+b^2

or,h^2=(8)^2+(8)^2

or,h^2=64+64

or,h^2=128

or,h=√128

or,h=8√2

h=11.31 cm

hope it helps

Good luck on your assignment