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trapecia [35]
3 years ago
6

La media de una población es 683.5g y su desviación estándar 52.1g. Determina la puntuación estándar para el valor 652.1​

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Respuesta:

- 0,60

Explicación paso a paso:

Dado que:

Media poblacional, μ = 683,5

Desviación estándar, σ = 52,1

Puntuación, x = 652,1

La puntuación estandarizada, Z = (x - μ) / σ

Puntuación Z = (652,1 - 683,5) / 52,1

Puntuación Z = - 31,4 / 52,1

Zscore = −0.602687

Puntaje estandarizado = - 0.60

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The percentage of the revenue is 32% hope this helps!
4 0
3 years ago
Triangle ABC has a right angle at angle c and pounts e,d and f are midpoints. Line df = 3 and line segment ab= 10. What is the l
Leni [432]
See the attached figure.
========================
AB = 10 , FD = 3
∵ D is the midpoint of AB, and F is the mid point of CB
∴ FD // AC , FD = 0.5 AC
∵ Δ ABC is a right triangle at C
∴ FD ⊥ BC
∴ BD = 0.5 AB = 5
∴ in Δ FDB ⇒⇒ BF² = BD² - FD² = 5² - 3² = 16
∴ BF = √16 = 4
∵ F is the mid point of CB 
∴ CF = BF = 4 , and CB = 2 BF = 2*4 = 8
∵ D is the midpoint of AB, and E is the mid point of AC
∴ DE // CB  , and DE = 0.5 CB = 0.5 * 8 = 4

∴ T<span>he length of line ED is 4
</span>



8 0
3 years ago
Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals
LenaWriter [7]

Answer:

It will take 35.46 quarters for the account to grow to $3000.

Step-by-step explanation:

Since the annual rate is compounded quarterly, this can be calculated using the formula for calculating the future value as follows:

FV = PV * (1 + r)^n ............................ (1)

Where;

FV = future value or the amount the deposit expected to grow to = $3,000

PV = Present value or the amount place in the savings = $2,000

r = Quarterly rate = Annual rate / 4 = 4.6% / 4 = 0.046 / 4 = 0.0115

n = number of quarters it will take for the loan to grow to $3000 = ?

Substituting the values into equation (1) and solve for n, we have:

$3,000 = $2,000 * (1 + 0.0115)^n

$3,000 / $2,000 = (1.0115)^n

1.50 = (1.0115)^n

Loglinearise both sides, we have:

log(1.50) = n log(1.0115)

0.176091259055681 = n * 0.00496588710682352

n = 0.176091259055681 / 0.00496588710682352

n = 35.4601816891322

Rounding to the nearest hundredth, which also implies to rounding to 2 decimal places, we have:

n = 35.46

Since the the annual rate is compounded quarterly, it will therefore take 35.46 quarters for the account to grow to $3000.

3 0
2 years ago
The interest on a $6,000, 6%, 60-day note receivable is
Musya8 [376]

Answer:

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Step-by-step explanation:

4 0
3 years ago
What adds to get 3 but multiplies to get negative 18
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6 and -3

6 + -3 = 3

6  x -3 = -18

Hope that helps! 
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