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3 years ago

Musa is 47 years old and Dayo is 22 years old. How many years ago was the product of their ages i.e 836 years.

Mathematics

1 answer:

shtirl [24]3 years ago

8 0

Answer:

3 years ago

Step-by-step explanation:

let m be Musa's age and d be Dayo's age

let x be number of years ago

m = 47

d = 22

(m - x)(d - x) = 836

(47 - x)(22 - x) = 836

1034 - 69x + x² = 836

x² - 69x + 198 = 0

This is in standard from ax² + bx + c = 0

Factor to be (x+q)(x+p)=0

p*q = c = 198

p+q = b = -69

198 = (-3)*(-66)

(-3) + (-66) = -69

Factored form is:

(x - 66)(x - 3) = 0

Set each bracket to 0

x - 66 = 0

x = 66 <= This number is inadmissable because neither Musa nor Dayo reached age 66.

x - 3 = 0

x = 3

The product of their ages was 836 3 years ago.

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2 years ago

Comparing the two ratios 2/4 and 1/2 2/4 is larger

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Step-by-step explanation:

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Solution:

Express the given ratios as fraction

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Now find the L.C.M (least common multiple) of 6 and 9

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Making the denominator of each fraction equal to 18, we have

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Clearly, 15 > 14

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3. Compare the ratios 1.2 : 2.5 and 3.5 : 7.

Solution:

1.2 : 2.5 = 1.2/2.5 and 3.5 : 7 =3.5/7

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[We removed the decimal point from the ratios now, we will compare the ratio]

Now find the L.C.M (least common multiple) of 25 and 2

The L.C.M (least common multiple) of 25 and 2 is 50.

Making the denominator of each fraction equal to 50, we have

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Now, 25/50 > 24/50

Therefore, 3.5 : 7 > 1.2 : 2.5.

4 0

3 years ago

Musa is 47 years old and Dayo is 22 years old. How many years ago was the product of their ages i.e 836 years.​

Musa is 47 years old and Dayo is 22 years old. How many years ago was the product of their ages i.e 836 years.