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lidiya [134]
3 years ago
13

Write the slope-intercept form of the equation for the line. a. y=-8/7x+3/2 b.y= -3/2x+7/8 c.y=-7/8x-3/2 d.y=7/8x+3/2 Write the

slope-intercept form of the equation for the line.

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

c)

Step-by-step explanation:

(-4,2)  ; (4,-5)

Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-5-2}{4-[-4]}\\\\=\frac{-7}{4+4}\\\\=\frac{-7}{8}

m = -7/8 ;   (-4,2)

equation: y - y1 = m(x - x1)

y-2=\frac{-7}{8}(x-[-4])\\\\y-2=\frac{-7}{8}(x+4)\\\\y-2=\frac{-7}{8}x +\frac{-7}{8}*4\\\\y=\frac{-7}{8}x-\frac{7}{2}+2\\\\y=\frac{-7}{8}x-\frac{7}{2}+\frac{4}{2}\\\\y=\frac{-7}{8}x-\frac{3}{2}\\

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when x = -14

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Answer

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juin [17]

Answer:

1- 4x -7 =29, x= 9

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Step-by-step explanation:

4x-7 =29

4x= 29 +7

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x/3 = 12+ 8

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x= 60

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3 years ago
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Ahat [919]

Answer:

x = 2

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2) Subtract 32 : -8x = 7x - 30

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3 years ago
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Line j has an equation of y - 8 = -2/3(x+5). Line K is perpendicular to line j and passes + through (-6, -2). What is the equati
riadik2000 [5.3K]

Answer:

y = \frac{3}{2} x + 7

Step-by-step explanation:

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y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

y - 8 = - \frac{2}{3} (x + 5) ← is in point- slope form

with m = - \frac{2}{3}

given a line with slope m then the slope of a line perpendicular to it is

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the equation of a line in slope- intercept form is

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2 years ago
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Answer:

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6+4/5b=9/10b

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