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3 years ago

Ireland has a 23% VAT (value-added tax, similar to a sales tax). How much will the VAT be on a purchase of a €250 item?

Mathematics

2 answers:

rjkz [21]3 years ago

7 0

Answer: The amount of VAT on a purchase of an item is $57.5.

Step-by-step explanation:

Since we have given that

Cost of item = $250

we need to find the amount of VAT.

Rate of VAT = 23%

So, amount of VAT would be

$\dfrac{23}{100}\times 250\\\\=0.23\times 250\\\\=\$57.5$

Hence, The amount of VAT on a purchase of an item is $57.5.

Maurinko [17]3 years ago

5 0

€250 x 1.23 (123%) = €307.50

:)

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A dog has a 25 ft leash attached to a corner where a garage and fence meet. When the dog pulls the leash tight and walks from th

dalvyx [7]

Answer: $170^{\circ}$

Step-by-step explanation:

Given

The dog has a 25 ft leash

Arc length is 74.3 ft

Arc length is given by

$l=\dfrac{\theta }{360^{\circ}}\times 2\pi r$

here, r=25 ft

l=74.3 ft

Put the values

$\Rightarrow 74.3=\dfrac{\theta }{360^{\circ}}\times 2\pi \times 25\\\\\Rightarrow \theta =170.2^{\circ} \approx 170^{\circ}$

The measure of the angle is $170^{\circ}$

7 0

2 years ago

What are three equivalent ratios for 6 to 54

mariarad [96]

6:54

6 to 54

6/54

Those are the three ratios

4 0

3 years ago

Read 2 more answers

Yesterday Mike bought 2 gallons of regular gasoline and 3 gallons of premium gasoline at a gas station for $13.60 today he bough

larisa [96]

Answer:

Cost of 1 gallon of Regular gasoline is $2.45 and Cost of 1 gallon of Premium gasoline is $2.90.

Step-by-step explanation:

Let the Cost of Regular gasoline be 'x'.

Let the Cost of Premium gasoline be 'y'.

Given:

Amount of regular gasoline bought yesterday = 2 gallons

Amount of premium gasoline bought yesterday = 3 gallons

Total Cost of yesterday = $13.60

Now we know that Total Cost of yesterday is equal to sum of Amount of regular gasoline bought yesterday multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought yesterday multiplied by Cost of premium gasoline.

Framing in equation form we get;

$2x+3y=13.60 \ \ \ \ equation\ 1$

Also Given:

Amount of regular gasoline bought today = 3 gallons

Amount of premium gasoline bought Today = 4 gallons

Total Cost of Today = $18.95

Now we know that Total Cost of Today is equal to sum of Amount of regular gasoline bought Today multiplied by Cost of Regular gasoline and Amount of Premium gasoline bought Today multiplied by Cost of premium gasoline.

Framing in equation form we get;

$3x+4y=18.95 \ \ \ \ equation\ 2$

Now Multiplying equation 1 by 3 we get;

$2x+3y=13.60\\\\3(2x+3y)=13.60\times3\\\\6x+9y= 40.80 \ \ \ \ \ equation\ 3$

Now Multiplying equation 2 by 2 we get;

$3x+4y=18.95\\\\2(3x+4y)=18.95\times2\\\\6x+8y= 37.90 \ \ \ \ \ \ equation\ 4$

Subtracting equation 4 from equation 3 we get;

$(6x+9y)- (6x+8y)= 40.80-37.90\\\\6x+9y-6x-8y= 2.9\\\\y=\$2.90$

Substituting the value of y in equation 1 we get;

$2x+3y=13.60\\\\2x+3\times2.90 =13.60\\\\2x+8.7=13.6\\\\2x=13.6-8.7\\\\2x=4.9\\\\x=\frac{4.9}{2} =\$2.45$

Hence Cost of 1 gallon of Regular gasoline is $2.45 and Cost of 1 gallon of Premium gasoline is $2.90.

4 0

2 years ago

Pls help me i need it to move on i did so many i cant figure it out.

lukranit [14]

Answer:

B. Between 200 and 400

Step-by-step explanation:

Rule of exponents means that you can subtract when they are divided

-5+7=2

7.8*10^2/3.1

Simplify

780/3.1= 251.612903

5 0

2 years ago

7th term of (c-d)^10

lutik1710 [3]

$\bf (c-d)^{10}\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&+1&(c)^{10}(-d)^0\\
2&+10&(c)^9(-d)^1\\
3&+45&(c)^8(-d)^2\\
4&+120&(c)^7(-d)^3\\
5&+210&(c)^6(-d)^4\\
6&+252&(c)^5(-d)^5\\
7&+210&(c)^4(-d)^6
\end{array}$

as you notice, the first term from the binomial, starts off with a highest exponent of 10, and then gradually goes down by 1 on every element.

the second term of the binomial, starts off with an exponent of 0, and goes up by 1 on every element.

now, to get the coefficient
the first coefficient is 1 and the second is the same as the binomial's exponent... those two are simple.... now, to get any subsequent one, we simply "get the product of the current coefficient and the exponent of the first term, and divide it by the exponent of the second term on the next element".

for example... how do we get 10 for the second element, basically 1 * 10/1

that one is simple

now how do we get say, 45 for the 3rd element?
10 * 9 / 2

how do we get 252 for the 6th element?
210 * 6 / 5

and so on, and from there, you can expand each element.

4 0

3 years ago