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2 years ago

7

Solve for x and y 4x, 15 X + 12, 3y(it's for a parallelogram)

1 answer:

yan [13]2 years ago

7 0

Answer:

done on peace of paper

Step-by-step explanation: bro this was so easy how do you not know this

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18. Mabel gave Margo a bag containing red, white, and

Sedbober [7]

So if the bag contains half as many red marbles as blue ones, and there are 8 reds then there are 16 blues. 16 + 8= 24 if you want there to be 1/4 white marbles add 6. 6/30 is 1/4.

So the answer comes out to be 30 marbles in the bag

4 0

2 years ago

Read 2 more answers

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$

And the standard deviation of the distribution of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74$

Thus, the distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b)

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the value of $P(\bar X$ is 0.7642.

(c)

Compute the value of $P(\bar X\geq 69.1)$ as follows:

Apply continuity correction as follows:

$P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)$

$=P(\bar X>69.6)$

$=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})$

$=P(Z>0.34)\\=1-P(Z$

Thus, the value of $P(\bar X\geq 69.1)$ is 0.3670.

7 0

3 years ago

Marking brainliest right away!!!!

GarryVolchara [31]

Answer:

(-3,-1)

Step-by-step explanation:

When you graph it on a graphing paper, you can see that the graph touches it but barely

4 0

3 years ago

Simplify – 5(7 + x) + 2x.

IgorLugansk [536]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

7 0

3 years ago

Read 2 more answers

A researcher at a major clinic wishes to estimate the proportion of the adult population of the United States that has sleep dep

Thepotemich [5.8K]

Answer: n = 600.25 ≈ 601 ( sample size)

the minimum sample size of the adults in United State who have sleep deprivation is 601

Step-by-step explanation:

Given that;

the confidence level = 95% = 0.05

the Margin of error E = 4% = 0.04

∴ level of significance ∝ = 1 - C.L

∝ = 1 - (95/100)

= 0.05

Z∝/2 = 0.05/2 = 0.025

Z-critical value at 95% confidence level is OR level of significance at 0.025 = 1.96 (z-table)

Now to calculate the sample size, we say

n = (Z(critical) / M.E )² P ( 1 - P)

now we substitute

n = (1.96 / 0.04)² × 0.5 ( 1 - 0.5)

n = 2401 × 0.5 × 0.5

n = 600.25 ≈ 601

Therefore the minimum sample size of the adults in United State who have sleep deprivation is 601

6 0

3 years ago