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Len [333]
3 years ago
13

I need help please, I attached a photo.Graph y>1-3x

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0
Your answer is the one on the bottom left
You might be interested in
What is the sixth term of (a - y)7?<br><br> 21a3y4<br><br> -21a3y4<br><br> 21a2y5<br><br> -21a2y5
Katena32 [7]
Im guessing the fourth answer
3 0
3 years ago
the odds of rolling a certain number on a single die is 1 chance in 6 rolls. in course of a game, someone rolled 3 fives. accord
Zina [86]

Answer:

18

Step-by-step explanation:

The expected value is the probability times the frequency.

3 = 1/6 × n

n = 18

Note: the use of the word "odds" is very misleading here.  Odds are the ratio of number of successes to number of failures:

S / F

Probability is the ratio of number of successes to number of all outcomes:

S / (S + F)

So the probability of rolling a 5 is 1/6.  The odds of rolling a 5 is 1/5.

Furthermore, the word "must" is also incorrect.  The player didn't <em>have</em> to roll 18 times.  They could have rolled three times and gotten a 5 each time.  Or they could have rolled 100 times.  18 is simply the most <em>likely </em>number of rolls needed to get three 5's.

6 0
3 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
What is 100÷77 i really need help urgent
MAVERICK [17]

\frac{100}{77}  = 1,2987012987012
3 0
3 years ago
Read 2 more answers
then difference between the cubes of two numbers is twice the value of the perfect square of a possitive Intiger
PSYCHO15rus [73]
There are many solutions. But what do you mean with a perfect square of a number. I thought a number IS a perfect square or not.

For example, the difference between 2² and 4² = 12, which is twice the number 6, which is √36

The difference between 2² and 6² = 32, which is twice the number 16, which is a perfect square.

So choose depending on your interpretation of the question... ;-)
8 0
3 years ago
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