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Maurinko [17]
3 years ago
11

darren has 3/4 of a gallon of soil.he needs to plant 5 small plants.if he splits the soil evenly between the plants.how much soi

l will each plant get?
Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0
3/4 divides by 5

3/4 x 1/5 = 3/20 of a gallon
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Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [
Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx

Using this we can say that

\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = \frac{12}{6} =2

Answer is 2

7 0
3 years ago
☕️Easy points for those who are good at math☕️
Eddi Din [679]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
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Determine the solution to the system of equations graphed below and explain
lawyer [7]

If x - 4 ≥ 0, then |x - 4| = x - 4, so

G(x) = F(x)   ⇒   3x + 2 = (x - 4) + 2

⇒   3x + 2 = x - 2

⇒   2x = -4

⇒   x = -2

Otherwise, if x - 4 < 0, then |x - 4| = -(x - 4), so

G(x) = F(x)   ⇒   3x + 2 = -(x - 4) + 2

⇒   3x + 2 = -x + 6

⇒   4x = 4

⇒   x = 1

However,

• when x = -2, we have

G(-2) = 3(-2) + 2 = -4

F(-2) = |-2 - 4| + 2 = 8

• when x = 1, we have

G(1) = 3(1) + 2 = 5

F(1) = |1 - 4| + 2 = 5

so only x = 1 is a solution to G(x) = F(x).

7 0
2 years ago
The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki
Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

t is the number of months since January.

Now, we use a cosine curve to model this scenario

Vertical shift will be;

D = ( 6 + 14 ) / 2 = 20 / 2

D = 10

Next is the Amplitude;

|A| = ( 6 - 14 ) / 2

|A| = 4

Now, the horizontal stretch factor will be;

B = 2π / 12

B = π/6

Hence;

S(t) = 4cos( π/6 × t ) + 10 ----------- let this be equation 1

Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

9 - 10 = 4cos( π/6 × (t-2) )

-1 = 4cos( π/6 × (t-2) )

-1/4 = cos( π/6 × (t-2) )

so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2)  -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

6 0
3 years ago
Find the percent of tip:
r-ruslan [8.4K]
The answer is 14%

Cost of meal is 100%:         $18.50 is 100%
Tip is x%:                             $2.59 is x

Make a proportion:
$18.50 : 100% = $2.59 : x
x = 100% * $2.59 : $18.50
x = 14%
4 0
3 years ago
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