Question

Please answer this....​

Answer 1

Answer:

c)    $2\frac{23}{30}$     d)$1\frac{23}{24}$

7)    a.   $6\frac{3}{11}$  kg                  b.   $6 \frac{2}{3}$  cm               c. 20 cm

 

d.  $9\frac{9}{10}$ kg                  e. 10 g             f. $23 \frac{1}{4}$  kg

Step-by-step explanation:

c)  $8\frac{2}{3}$   -   $5\frac{9}{10}$

First we will change to improper fraction and then solve

$\frac{26}{3} - \frac{59}{10}$

=  $\frac{260 - 177}{30}$

= $\frac{83}{30}$

we will now change to mixed number

= $2\frac{23}{30}$

d)  $8\frac{1}{8} - 6\frac{1}{6}$

we will first change it to improper fraction and then solve

= $\frac{65}{8} - \frac{37}{6}$

= $\frac{390 - 296}{48}$

= $\frac{94}{48}$

we can reduce the fraction

=$\frac{47}{24}$

we will change it mixed number

=$1\frac{23}{24}$

7)  

a.   $\frac{3}{11}$   of 23

=  $\frac{3}{11}$   × 23

=  $\frac{69}{11}$

=$6\frac{3}{11}$  kg

b. $\frac{2}{3}$   of 10 cm

= $\frac{2}{3}$   × 10 cm

= $\frac{20}{3}$  cm

=$6 \frac{2}{3}$  cm

c. $\frac{5}{6}$   of 24cm

=    $\frac{5}{6}$   × 24 cm

6 will divide 24

=5 × 4 cm

= 20 cm

d.  $\frac{3}{10}$  of  33 kg

=  $\frac{3}{10}$  ×  33 kg

=$\frac{99}{10}$  kg

=$9\frac{9}{10}$ kg

e. $\frac{2}{7}$   of  35 g

=  $\frac{2}{7}$   ×  35 g

7 will go into 35

=2×5 g

=10 g

f. $\frac{3}{4}$  of  31 kg

= $\frac{3}{4}$  ×  31 kg

=$\frac{93}{4}$ kg

=$23 \frac{1}{4}$  kg