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Nata [24]
3 years ago
9

A ladder that is 32 ft long leans against a building. The angle of Elevation of the Ladder is 70 degrees

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

B. 30 ft

Step-by-step explanation:

The ladder is 32 ft long

The angle of elevation of the ladder is 70°

The height (h) of the top of the ladder to the ground is what we are to find.

\frac{h}{32} = sin 70°

h = 32 × sin 70° = 30.07016387 or 30 ft (rounded off to nearest feet)

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Sphinxa [80]
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Look at the picture below for the question i need help with. I pretty sure you need to find the y-intercept...
daser333 [38]

Answer:

20.00

Explanation:

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8 0
2 years ago
The map shows the route for a race.You are at X, 6000 ft from the first checkpoint C.The second checkpoint D is located at the m
Alex

Answer:

Distance between the two check point (C and D) is 4920 ft.

Step-by-step explanation:

From the question given above, we obtained the following information:

X is 6000 ft from C (1st check point)

D (2nd check point) is the midpoint point between C and Y ( the end of the race)

Total race = 3 miles

1 mile = 5280 ft

Next, we shall express the total race in feet (ft).

This is illustrated below:

1 mile = 5280 ft

Therefore,

3 miles = 3 × 5280 = 15840 ft

Next, we shall determine the distance between the 1st check point (C) and the end of the race (Y)

This can be obtained as follow:

Total distance = 15840 ft

Distance between X and C = 6000 ft

Distance between C and Y =?

Distance between C and Y = (Total distance) – (Distance between X and C)

Distance between C and Y = 15840 – 6000

Distance between C and Y = 9840 ft

Finally, we shall determine the distance between the two check point (C and D) as follow:

Since D is midpoint between C and Y, therefore, we shall we shall divide the distance between C and Y by 2 in order to obtain the distance between the two check point (C and D).

This is illustrated below:

Distance between C and Y = 9840 ft

Distance between the two check point (C and D) = 9840/2 = 4920 ft

Therefore, the distance between the two check point (C and D) is 4920 ft

5 0
2 years ago
A helpful hand please
Tpy6a [65]
\bf s=\sqrt{2gh}\quad 
\begin{cases}
s=speed\\
g=gravity\\
h=height\\
-----\\
s=34\\
g=32
\end{cases}\implies s^2=2gh\\\\\\ \cfrac{s^2}{2g}=h\implies \cfrac{34^2}{2\cdot 32}=h
3 0
3 years ago
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