Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output
It most likely can but It may damage your system. So you should seek out professional help from a car dealership and do more research.
Hope this helps.<span />
Answer:
Statement to assign 32 to variable cheeses.
cheeses=32;
Explanation:
To assign any value to a variable in any programming language, we use "="operator.First declare a variable "cheeses"of type "int" in this case.Then assign 32 to variable "cheeses" with the help of "=" operator.After assigning 32 , variable will store 32 in it.
Implementation in c++.
#include <bits/stdc++.h>
using namespace std;
int main()
{
int cheeses;
cheeses=32;
return 0;
}
The process of combining information from a variety of sources
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
