1st we combine like terms
1.6b minus 8b which equals -6.4b
Now right out your new expression
-6.4b - 17.28 = -5.7b - 14.83
Now add 5.7 to both side
-6.4b - 17.28 = -5.7b - 14.83
+5.7b +5.7b
This should get you what bellow and then add +17.28 to both sides
-0.7b - 17.28 = -14.83
+17.28. +17.28
Almost done..
Now you're left with
_-0.7b___ = _2.45___
-0.7b. -0.7b
Answer= -3.5
This app messed up the order of the numbers so I hope you can understand where things go
K(a) = b^a = 0.2
k(-3a) = b^(-3a) = (b^a)^(-3)
= 0.2^(-3)
k(-3a) = 125
Answer:
C. The cost of a box of cereal
Step-by-step explanation:
In the question, we are given the number of 3 boxes of cereal, 2 loaves of bread, and that the total cost is $15. We can see these numbers in the equation, and putting it into context, we see that the 15 is on the right side of the equation, which indicates cash. Therefore, the 3 and 2 are accounted for, but their prices are unknown. X is a placeholder for the unidentified cost of a box of cereal, and we know that it's the boxes of cereal and not the loaves of bread because there are 3 and not 2.
The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u></u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.