Question

If f(x)=-8x+4, then f^-1=

Answer 1

Answer:

$f^{-1}$(x) = $\frac{4-x}{8}$

Step-by-step explanation:

let y = - 8x + 4

rearrange making x the subject

add 8x to both sides

8x + y = 4 ( subtract y from both sides )

8x = 4 - y ( divide both sides by 8 )

x = $\frac{4-y}{8}$

change y back into terms of x, then

$f^{-1}$(x) = $\frac{4-x}{8}$