Ask question

Ask question

All categories

3 years ago

13

A restaurant bill before tax is $15.50. If the sales tax is 8% and a 15% tip is added, what is the total cost of the meal? - Do

not pay taxes on the tip.

1 answer:

NikAS [45]3 years ago

4 0

The answer to this question should be
<span>$ 19.07</span>

You might be interested in

Please help me with this question and thank you for your help

Volgvan

The question is asking for the pattern of change within the given numbers. As you can see, the number decreases by 0.02 from left to right. Therefore, D is the correct answer. The whole number and tenths place remains constant as the hundredths place lowers by 2.

4 0

3 years ago

Read 2 more answers

In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known

mote1985 [20]

Answer:

arc BF = 76°
∠M = 31°
∠BGE = 121°
∠MFB = 111°

Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

arc BF = 2∠FBM = 2(38°)

arc BF = 76°

__

(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

∠M = (1/2)(138° -76°) = 62°/2

∠M = 31°

__

(c) arc FC is the supplement to arc BF, so has measure ...

arc FC = 180° -arc BF = 180° -76° = 104°

∠BGE is half the sum of arcs BE and FC, so is ...

∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

∠BGE = 121°

__

(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

∠MFB = 111°

3 0

4 years ago

Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2

Serggg [28]

${\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}$

$\small\color{blak}{{\underline{\bold{ Find \:a X } } } }$

$\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}$

$\small\color{blak}{{\underline{\bold{ Find\:a\:m$

$\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m$

$\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}$

7 0

3 years ago

Explain how to write the number that is 0.02 less than 1.423

Katyanochek1 [597]

Less than means subtract. So, 0.02 less than 1.423 is 1.423 - 0.02 which equals >>> 1.403

6 0

3 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

4 years ago