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kupik [55]
3 years ago
12

Pete’s grade on a test was within 5 points of his class average of 94. What is his range of grades on the test?

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0
I'm pretty sure it would be 89-99.
irga5000 [103]3 years ago
6 0

Answer: 89 to 99

Step-by-step explanation:

We know that the range of data is given by :-

\overline{x}\pm E, where \overline{x} ios the average of data and E is the margin of error.

Given : Margin of error = \pm 5

Class average = 94

Then, the range of grades on the test will be :-

94\pm 5=(94-5,\ 94+5)=(89,\ 99)

Hence, the range of grades on the test = 89 to 99

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olga55 [171]

The correlation coefficient of the health research institute data measures the relationship between the age and the years of the smokers

The correlation coefficient is 0.53

<h3>How to calculate the correlation coefficient</h3>

The correlation coefficient (r) is calculated as:

r = \frac{n(\sum xy) - \sum x \sum y}{\sqrt{[n \sum x^2 - (\sum x)^2][n\sum y^2 - (\sum y)^2}}

Using the given parameters, we have:

r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1257^2][20 * 836 - 116^2}}

Evaluate the exponents

r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1580049][20 * 836 - 13456}}

Evaluate the products

r = \frac{164980 - 145812}{\sqrt{[1976460 - 1580049][16720 - 13456}}

Evaluate the differences

r = \frac{19168}{\sqrt{[396411*3264}}

Evaluate the product

r = \frac{19168}{\sqrt{1293885504}}

Evaluate the root

r = \frac{19168}{35970.6}

Evaluate the quotient

r = 0.53

Hence, the correlation coefficient is 0.53

Read more about correlation coefficient at:

brainly.com/question/1564293

8 0
2 years ago
HELP PLEASE!!!!! Solve each system.
Ede4ka [16]

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3 years ago
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djverab [1.8K]
So 4.5 is equal to 4 and 1/2 
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