I think C but probably try to find something to back it up
All you gotta do is divide the pound by the cost
Answer:
×1 = 3 : 8.
×2 = 6 : 16
×3 = 9 : 24
×4 = 12 : 32
Step-by-step explanation:
<span>3sinx+4cosx=5
=> 3/5 sinx +4/5 cosx = 1
let cosA=3/5 => sinA=4/5
=> cosAsinx + sinAcosx = 1
=> sin(x+A) = 1
Now,
4sinx - 3cosx
= 5(4/5sinx - 3/5 cosx) [multipying numerator and denominator by 5]
= 5(sinAsinx - cosAcosx)
= -5{cos(x+A)} = -5[root{1-(sin(x+A)^2)}] = -5 x 0 = 0 Ans 0
TRICK: if asinx+bcosx is given then multiply numerator and denominator by root(a^2 +b^2)
this method is useful in many questions </span>
<span>1. Set up the equation. On a piece of paper, write the dividend (number being divided) on the right, under the division symbol, and the divisor (number doing the division) to the left on the outside.
2. Divide the first digit.
3. Divide the first two digits.
<span>4. Enter the first digit of the quotient.</span></span>
