4b + 21 = −3(b − 7) + 7b
1 answer:
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Answer:
4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.
Step-by-step explanation:
Let the three consecutive numbers be x, (x+1), (x+2)
Now, the squares of these three numbers are
Sum = 77
∴by the problem ,
{Taking 3 common }
{By factorization}
Therfore,
<em>X can't be negetive </em>
∴
The squares of the three consecutive numbers are 16, 25, 36
The three consecutive numbers whose sum is 77 are 4, 5, 6