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ludmilkaskok [199]
3 years ago
13

Use of antibiotics in animal feed leads to antibiotic-resistant bacteria because

Biology
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

The correct option is D.

Explanation: The options attached to this question are given below:

A) Bacteria from other animals replace those killed by the antibiotics.

B) The few surviving bacteria that are affected by the antibiotics develop immunity to the antibiotics, which they pass on to their progeny.

C) The antibiotics cause new mutations to occur in the surviving bacteria, which results in resistance to antibiotics.  

D) The antibiotics kill susceptible bacteria, but the few that are naturally resistant live and reproduce, and their progeny repopulate the host animal.

E) The antibiotics persist in soil and water.

Antibiotics are sometimes used in animals to control infections. With time, the microbes that are been targeted with the antibiotics usually develop mutations, which makes the antibiotics to become ineffective, thus, the antibiotics will only be able to kill the susceptible microbes while the ones that have developed resistance will remain and give birth to young ones that are also resistant to antibiotics.

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Veronika [31]

Answer:

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5 0
2 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Agata [3.3K]

Answer:

2,855 is the size of the colony of mosquitoes after 4 ​days.

Explanation:

The law of uninhibited growth is given as:

A=A_o\times e^{k\times t}

A_o= Original amount

A = Amount after time t

k = Positive constant repressing the rate of growth

We are given with:

Original population of mosquitoes = 1000

Population of mosquitoes after 1 day =1300

t = 1 day

1300=1000\times e^{k\times 1 day}

k = 0.2623 day^{-1}

Population size of mosquitoes after 4 days

A_o=1000, k= 0.2623 day^{-1}

A =? , t = 4 days

A=1000\times e^{ 0.2623 day^{-1}\times 4 days}

A =2,855.36 ≈ 2,855 mosquitoes

2,855 is the size of the colony of mosquitoes after 4 ​days.

5 0
3 years ago
Read 2 more answers
A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by
bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that  <em>the</em><em> probability</em><em> that, given enough time, all tigers in the population will have horizontal stripes is</em><em> 30% = 0.3.</em>

--------------------------

<u>Available data:</u>

  • Population size, N = 100 tigers
  • Number of Tigers with horizontal stripes = 30
  • Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

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6 0
2 years ago
A newborn is suspected of having fetal alcohol syndrome. which finding would the nurse expect to assess?
yan [13]
The answer is A. flattened maxilla.
5 0
3 years ago
Chlamydomonas contains ___ to carry out the process of ___​
Advocard [28]

Answer:

Chlamydomonas containsingle-cell green alga to carry the procces of photosntesis

Explanation:

3 0
2 years ago
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