Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
The answer is D because then triangles DEF and ABC would mapped onto one another
Answer:
x+3y = 6
or, x = 6-3y.................(1)
3x+5y =6..........(2)
Substituting x = 6-3y in equation (2),
3 (6 - 3 y)+5 y =6
or, 18 - 9y +5y=6
or, y = 3
x = 6 - 3y = 6- 3.-3 = -3
The greatest common factor would be 5u^2v^2. Hope this helps!
Answer:
48 + 12√3 units
Step-by-step explanation:
ALL LENGTHS MUST BE POSITIVE (I did this to avoid writing ± and showing that only + works)
1. Find AD (you'll find why later): 15² = 9² + AD² --> AD² = 144 --> AD = 12
2. 30-60-90: 12-DC-AC --> AC = 24, DC = 12√3 (side opposite of 90 is double side opposite of 30, side opposite of 60 is √3 times the opposite of 30)
P = AB + BD + DC + AC = 15 + 9 + 12√3 + 24 = 48 + 12√3 units
