Answer:
Get photomath its free and all you need is a camra
Step-by-step explanation:
Answer:
0.3
Step-by-step explanation:
Answer:
The answer is A.
Step-by-step explanation:
There are Four 6's, Four 4's, Seven 5's, One 2, Two 3's, Two 7's, and One 8.
Hope this helps :))
Answer:
x = 3/2 or x = -5/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 2 x - 15 = 0
Using the quadratic formula, solve for x.
x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:
x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16
Simplify radicals.
sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:
x = (2 + 22)/16 or x = (2 - 22)/16
Evaluate (2 + 22)/16.
(2 + 22)/16 = 24/16 = 3/2:
x = 3/2 or x = (2 - 22)/16
Evaluate (2 - 22)/16.
(2 - 22)/16 = -20/16 = -5/4:
Answer: x = 3/2 or x = -5/4
From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325 See explanation below.
<h3>
What are the step by steps solution to the questions above?</h3>
First, lets us restate the question properly. We have
Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
Note that there are three equals signs. So lets divide the problem according and solve for the different parts.
Lets 1 - ((6*12+6)/80)² ............A
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C
Solving for A we have
1 - (78/80)²
= 1 - (0.975)²
= 1 - 0.950625
A = 0.049375
Solving for B we have
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)
= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625
B = -8.050625
Solving for C we have
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144
= 0.0325
In summary we can state that:
A = 0.049375
B = -8.050625
C = 0.0325
Given that there were no abstract quantities, we can state that
Pr = A ≠ B ≠C or
Pr = 0.049375 ≠ -8.050625 ≠ 0.0325
Learn more about equations with equal signs at
brainly.com/question/18924248
#SPJ1
