What is the equation has intercepts at x(1, 0, 0), y(0, -1,0), and z(0, 0, 2)

Mathematics

1 answer:

bulgar [2K]3 years ago

3 0

In intercept form, the plane that has these intercepts is ...

... x/(x-intercept) + y/(y-intercept) + z/(z-intercept) = 1

... x/1 + y/(-1) + z/2 = 1

... 2x -2y +z = 2 . . . . . in standard form

You might be interested in

If you enter the formula =A2*(1+$A$1) in cell B2 and then copy cell B2 to C2, the numerical result in cell

denis-greek [22]

It’s is b 121 . Gang gang

6 0

3 years ago

A town has three roads that form an obtuse triangle. James wants to set up a refreshment stand so that the shortest distance fro

GarryVolchara [31]

He should set up the refreshment stand on the incenter of the obtuse triangle. The incenter of a triangle is described as the intersection between the angle bisectors of a triangle. The inradius are the line segments from the incenter of the triangle to each of the three sides of the triangle which are all equal. The inradius is depicted as the radius of an inscribed circle in the triangle. Therefore, the shortest equal distance from his stand to each road is C. on the incenter.

4 0

3 years ago

Given: JK tangent, KH=16, HE=12 Find: JK.

Y_Kistochka [10]

Answer: $JK=8$

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

$JK^2=KE*KH$