Answer:
At the microscopic level of a visceral muscle cell are actin and myosin filaments. They slide past each other in an antiparallel manner to shorten the distances between their ends. In a smooth muscle cell, the ends of chains of these functional units are attached to the cell membrane. They are several in a cell arranged in an elaborate framework. They contract together and deferentially to enable the muscle to contract as needed.
Answer:
1250 g=1.25 Kg
Explanation:
We are given that Jason has five fishes of equally massed lead fish weights.
Weigh of each fish =250 grams
We have to find the value of total mass of the five lead fishing weights
Total number of fishes=5
In order to find the total mass we will use unitary method
Total mass is obtained by multiplying the total number of fishes with weight of one fish
Total mass=
Total mass of five fishes=1250 g
1 kg =1000g
Then 1250 g=
Hence, total mass of five lead fishing weights=1250 g=1.25 Kg