All categories

3 years ago

Need help with simplifying this question

Mathematics

2 answers:

Digiron [165]3 years ago

5 0

${3}^{ - 3}$

hope this helps :)

mr Goodwill [35]3 years ago

3 0

Yo sup??

$(3^6)^-^1^/^2\\=3^6^*^(^-^1^/^2^)\\=3^(^-^3^)\\$

Therefore your answer is option A ie

A.3^(-3)

Hope this helps.

You might be interested in

A hiker standing at point G wants to estimate the distance across the lake to point H, which is directly north of her location.

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

The diagram is attached.

Looking at the diagram, we want the side "opposite" of the angle given and the side "adjacent" is given.

Which ratio relates opposite and adjacent? It is Tan.

We can use trigonometry and tan ratio to solve for the distance "x":

$Tan(84)=\frac{x}{650}\\x=Tan(84)*650\\x=6184.4$

D is the correct answer.

5 0

3 years ago

Find the LCM and the GCF of 100 and 120.

Advocard [28]

Answer:

Step-by-step explanation:

LCM is least common multiple. It means the least multiple that both 100 and 120 have in common. 600 is the LCM. 20 is the GCF.

4 0

3 years ago

Maria has 90$ in a saving account.The interest rate rise a 5% compounded annually.to the nearest cent, how much will he have in

-Dominant- [34]

Answer:

$104.19

Step-by-step explanation:

We will use the compound interest formula to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, lets change 5% into a decimal:

5% -> $\frac{5}{100}$ -> 0.05

Now, plug the values into the equation:

$A=90(1+\frac{0.05}{1})^{1(3)}$

$A=104.19$

After 3 years, Maria will have $104.19

8 0

3 years ago

A charter bus travels 225 miles in

xz_007 [3.2K]

D because y (time spent) = 50 × x (distance travelled)

225÷4.5=50

x÷y=50

5 0

3 years ago

A half of a class and a half of a student got A on a test. If yet another student got an A, then two-thirds of the class would h

Cerrena [4.2K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Need help with simplifying this question ​

Need help with simplifying this question