I believe it's b , hopefully this helps
Answer:
a. 3942 kWh
b. $473.04
c. 1314 kWh
d. $157.68
Step-by-step explanation:
<h3>a. </h3>
There are 1000 W in 1 kW, so 450 W = 0.450 kW. The energy used per day is ...
(0.45 kW)(24 h) = 10.8 kWh . . . . energy per day
Then in a 365-day year, the energy used is
(365 da/yr)(10.8 kWh/da) = 3942 kWh/yr
__
<h3>b.</h3>
At the rate of $0.12/kWh, the cost of running the pump is ...
($0.12/kWh)(3942 kWh/yr) = $473.04/yr
__
<h3>c.</h3>
Switching the pump off for 1/3 of the time will save 1/3 of the energy found in part (a):
1/3(3942 kWh) = 1314 kWh . . . . energy saved by switching off the pump
__
<h3>d.</h3>
The savings will be 1/3 of the cost of running the pump full time:
1/3($473.04/yr) = $157.68/yr
-|20| + |5| = -15
Steps:
Apply absolute rule: |a| = a, a >/ 0
|20| = 20
= -20+5
Apply absolute rule: |a| = a, a >/ 0
|5| = 5
= -20+5
Refine
= -15
Hope this helps you! (:
-Hamilton1757
The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
= (5 + 1)/10 hour
= 6/10 hour
= 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
= 4/(3/5) miles/hour
= (4 * 5)/3 miles/hour
= 20/3 miles/hour
= 6 2/3 miles/hour
= 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
Answer:
Are you taking edgnuity AP calculus
Step-by-step explanation:
