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3 years ago

11

Please help! need fast help!

1 answer:

Mice21 [21]3 years ago

6 0

Answer:

i think x = 146

Step-by-step explanation:

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Use the Properties of Equality to solve each equation.

castortr0y [4]

The answer is -25

All you have to do is add -6-9 which equals -25 because “same signs add(+) and keep” “different signs subtract(-)” but “add” means positive number and “subtract” means negative number. Since they are different signs a (+) and a (-) you subtract it.

Hope this helps!

6 0

1 year ago

Find the limit of the function algebraically.

ArbitrLikvidat [17]

$\bf \lim\limits_{x\to -10}~\cfrac{x^2-100}{x+10}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-10^2}}{x+10}\implies \cfrac{(x-10)(\underline{x+10})}{\underline{x+10}}
\\\\\\
\lim\limits_{x\to -10}~x-10\implies \lim\limits_{x\to -10}~-10-10\implies -20$

5 0

3 years ago

6) 9(x - 1)+ 4x<br><br>what's the answer

svet-max [94.6K]

Answer:

13x-9

Step-by-step explanation:

9×(x - 1)

9x - 9 +4x

collect like terms, 9x+4x=13x

4 0

3 years ago

Read 2 more answers

3) John and his two friends went out to lunch.

Delvig [45]

Answer:

they get 8.27$ back.

Step-by-step explanation:

Cost of lunch=$7.29+$8.45+$5.99

=$21.73

3 of them put $10 each=$10×3

$30

Total change they got back=$30-$21.73

=$8.27

Mark as a brainest answer ok

4 0

3 years ago

Find the area of each shaded region each outer polygon is regular <br><br><br> See the picture

PSYCHO15rus [73]

Answer:

Area of the shaded region = 3.46 square units

Step-by-step explanation:

Measure of the interior angle of a regular polygon = $\frac{(n - 2)\times180}{n}$

From the picture attached,

Number of sides of the given polygon 'n' = 6

Interior angle (∠BAF) of the given polygon = $\frac{(6 - 2)\times 180}{6}$

= 120°

Measure of ∠BAC = $\frac{120}{4}$

= 30°

Now we apply sine rule in ΔAGB,

sin(30°) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{BG}{AB}$

BG = AB[sin(30°)]

= $2\times \frac{1}{2}$

= 1

By applying cosine rule in ΔABG,

cos(30°) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

= $\frac{AG}{AB}$

AG = AB[cos(30°)]

= $2\times \frac{\sqrt{3} }{2}$

= $\sqrt{3}$

AC = 2(AG)

= 2√3

Area of ΔABC = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(AC)(BG)$

= $\frac{1}{2}(2\sqrt{3} )(1)$

= $\sqrt{3}$

Area of the shaded region = Area of ΔABC + Area of ΔFED

= 2(Area of ΔABC)

= 2√3

= 3.46 square units

6 0

3 years ago