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Answer: Choice B) 0.5</h3>
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Explanation:
For now, focus solely on the orange boxplot. The first quartile Q1 is the left edge of the box, which is at 3.5; while the value of Q3 is 7.5 (right edge of the box). The interquarile range (IQR) is ...
IQR = Q3 - Q1
IQR = 7.5 - 3.5
IQR = 4
This is basically the width of the box. Ignore the whiskers when it comes to the IQR.
Let A = 4 as we'll use it later.
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Find the IQR for the blue box plot
Q1 = 6 = left edge of the blue box
Q3 = 9.5 = right edge of the blue box
IQR = Q3 - Q1
IQR = 9.5 - 6
IQR = 3.5
Let B = 3.5 as we'll use it later
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Subtract the values of A and B to find the difference of the IQR values
A - B = 4 - 3.5 = 0.5
Answer:
The change in the total cost for each book printed is $10
The cost to get started is $1250
Step-by-step explanation:
In the linear equation y = m x + b, where
- m is the rate of change per unit
- b is the initial amount (value y at x = 0)
∵ y represents the total cost of publishing a book in dollars
∵ x represents the number of copies of the book printed
∵ y = 1250 + 10 x
- Compare it with the linear equation y = m x + b
∴ m = 10
∴ b = 1250
∵ m = Δy/Δx
- That means m is the change in the total cost per book
∴ The change in the total cost for each book printed is $10
∵ b is value y at x = 0
- That means b is the cost to get started before print any book)
∴ The cost to get started is $1250
Use PEMDAS.
17-(6×10÷2)+12
6×10=60 divide by 2 to get 30
now: 17-30+12
17-30=-13
-13+12=-1
It is not possible to write a sequence that is both arithmetic and geometric.
An arithmetic sequence is:
a0, a0 + d, a0 + 2d, a0 + 3d, ...
An geometric sequence is:
a0, a0r, a0r2, a0r3, ...
So if the two are equal, we have:
a0 = a0,
a0 + d = a0r,
a0 + 2d = a0r2,
a0 + 3d = a0r3,
...
This can only be true if d = 0 and r =1 and only for the first three terms. It's a trivial sequence with only three elements which can't be necessarily classified as a sequence.
