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borishaifa [10]
3 years ago
5

Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

we know that

If (x-8) is a factor of the function f(x)=-2x^{3}+17x^{2}-64

then

x=8 is a root of the function f(x)

therefore

For x=8 the value of the function must be zero

Verify

Substitute the value of x=8 in the function

f(8)=-2(8)^{3}+17(8)^{2}-64

f(8)=-2(512)+17(64)-64

f(8)=-1,024+1,088-64

f(8)=-1,088+1,088

f(8)=0

therefore

<u>the answer is</u>

Yes, (x-8) is a factor of the function f(x)

Usimov [2.4K]3 years ago
3 0
X-8=0
x=8
f(8)=-2(8)^3 +17(8)^2 - 64
=-2(512) + 17(64) - 64
 = -1024+1088-64
= -1024 -64+1088
= -1088+1088
=0

so, x-8 is a factor of the function f(x) = -2x3 +17x2 - 64

hope this helps!!!!!! ^_^_^


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