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katrin [286]
3 years ago
14

If QR=PQ , RS=PQ and QR is 2x+5 and RS is 10-3x Solve for x using the given information

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

2x + 5 = 10 - 3x

2x + 3x = 10 - 5

5x = 5

x = 1

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Catherine solved 4 × 9 = .
Aloiza [94]
The answer is b, because division checks multiplication.
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From the definition of absolute value, |3x|= when x>=0
devlian [24]
<h3>Answer:  3x</h3>

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4 0
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If middle school and senior school are winning football games in the ratio 3:9 . If the Middle school won 17 games, calculate ho
Helen [10]
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4 0
3 years ago
How many sixes go into 566?
alexandr402 [8]
566/6 = 94.3333333
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6 0
3 years ago
Show your work for factoring or quadratic formula:
lutik1710 [3]
First, I'd simplify this problem by dividing every term by 2:

x^4 - 4x^3 + 5x^2 - 4x + 4 = 0

Then I'd think of the possible factors of that constant term, 4:  They would be plus or minus 1, plus or minus 2, or plus or minus 4.

Let's try x = -4 as a possible root.  Setting up and using synthetic division:

      ____________________
-4  /   1   -4   5    -4    4
              -4   32
     ----------------------------
         1    -8  37

This result is not helpful.  So, try the possible root +4 instead:
       ________________
+4  /   1   -4   5    -4    4
                4    0   20   64
       ----------------------------
         1     0    5    16   68             4 is not a root because the remainder   
                                                    (68) is not zero.

Try x = 2:

       ________________
+2  /   1   -4   5    -4    4
                2   -4    2    -40
       ----------------------------
          1    -2   1    -2    0

2 is a root because the remainder is zero.

Continue this process until you've found the other 3 roots.

Hint:  Try  the possible root x = -2 with the following coefficients:

     ____________
-2 /  1   -2   1   -2

    ---------------------
5 0
3 years ago
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