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Lubov Fominskaja [6]
3 years ago
8

A lawn is in the shape of a trapezoid with a height of 7070 feet and bases of 4040 feet and 160160 feet. how many full bags of f

ertilizer must be purchased to cover the lawn if each full bag covers 40004000 square feet and only full bags of fertilizer can be​ bought?
Mathematics
1 answer:
Leni [432]3 years ago
7 0
Area of the trapezium = 1/2 (40 + 160) x 70
Area of the trapezium = 7000 ft²

One bag of fertilizer = 4000 ft²

Number of bags of fertilizer needed  = 7000 ÷ 4000 = 1.75 bags.

Since only full bags of fertilizer can be bought, 2 bags of fertilizer are needed.

------------------------------------
Answer: 2 bags of fertilizer
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108

Step-by-step explanation:

  1. volume = area  of the base * height
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Question 20(Multiple Choice Worth 1 points)
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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

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I think that the awnser is A because I think it is

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The parallel line to this one should have the same slope as the first one(-2x)

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