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3 years ago

9

What is the answer? I don’t understand this thing at all

1 answer:

barxatty [35]3 years ago

4 0

Answer: 117.8 rounded to tenth

117.81 rounded to hundredth

Step-by-step explanation:

Pi * 10^2 * 135/360

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Find the distance between the two points in simplest radical form.

sweet-ann [11.9K]

Answer:

3 $\sqrt{13}$

Step-by-step explanation:

Calculate the distance using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (- 9, 8) and (x₂, y₂ ) = (- 3, - 1)

d = $\sqrt{(-3-(-9))^2+(-1-8)^2}$

= $\sqrt{(-3+9)^2+(-9)^2}$

= $\sqrt{6^2+81}$

= $\sqrt{36+81}$

= $\sqrt{117}$

= $\sqrt{9(13)}$

= $\sqrt{9}$ × $\sqrt{13}$

= 3 $\sqrt{13}$

8 0

3 years ago

(9q r+6qr +20g)+(-6qr -qr -11q-4q r)=

Arte-miy333 [17]

4qr+20g-11q hopefully this would help you

6 0

3 years ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

so

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

3 years ago

What is 0.69696969 expressed as the quotient of two integers in simplest form?

timofeeve [1]

When written as the quotient of two integers,

   0.69696969 = <em>69,696,969 / 100,000,000 .</em>

<u>If</u> you had said that the ' 69 ' keeps repeating forever and never ends,
then that decimal would represent the fraction
   23 / 33 .

3 0

3 years ago

Urgent help needed...............

andreyandreev [35.5K]

Answer:

Option b is correct

$\{x | x \neq \pm 7, x\neq 0\}$ .

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

$h(x) = \frac{9x}{x(x^2-49)}$

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

$x(x^2-49) = 0$

By zero product property;

$x = 0$ and $x^2-49= 0$

⇒x = 0 and $x^2 =49$

⇒x = 0 and $x = \pm 7$

Therefore, the domain of the given function is:

$\{x | x \neq \pm 7, x\neq 0\}$

7 0

3 years ago

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