Answer:
Step-by-step explanation:
Given that the observed frequencies for the outcomes as follows:
To check this we can use chi square goodness of fit test.
(Two tailed test at 5% significance level)
Assuming equally likely expected observations are found out and then chi square is calculated as (0-E)^2/E
Df = 6-1 =5
Outcome Frequency Expected frequency (Obs-exp)^2/Exp
1 36 34.83333333 0.03907496
2 30 34.83333333 0.670653907
3 41 34.83333333 1.091706539
4 40 34.83333333 0.766347687
5 23 34.83333333 4.019936204
6 39 34.83333333 0.498405104
209 209 7.086124402
p value =0.214
Since p >alpha, we accept null hypothesis
It appears that the loaded die does not behave differently than a fair die at 5% level of significance
Since you didn't provide expression to see which one is equivalent,, I will simply solve the expression you provided. If you need help finding out which expression option is equivalent after I solve this for you,, let me know and I would be more than happy to help you figure it out.
The first step for solving this expression is to calculate the difference between 20 and 21. We can start solving this by keeping the sign of the number with the larger absolute value and subtract the smaller absolute value from it. This will look like the following:
-(21 - 20)
Now subtract the numbers and add it back into the expression.
-1 + 8y - 9y
Next we need to collect the like terms with a y variable by subtracting their coefficients.
(8 - 9)y
Calculate the difference in the parenthesis.
-1y
Remember that when the term has a coefficient of -1,, the number doesn't have to be written but the sign must remain.
-y
Lastly,, add this back into the expression to get your final answer.
-1 - y
Let me know if you have any further questions.
:)
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
The answer is A. it has two complex solutions
