4 years ago

Everything just the first one, please. Asap, thanks in advance!

Mathematics

1 answer:

alekssr [168]4 years ago

7 0

Question number one is 2/3

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Compute the conditional probabilities P(A|B) and P(B|A).

Oksanka [162]

Answer:

Step-by-step explanation:

Good evening ,

P(A|B) = P(A∩B)/P(B)

P(B|A) = P(A∩B)/P(A)

6 0

3 years ago

PLEASE HELP!!!!! I don’t get it all :((((

asambeis [7]

The answer is 35 hope this helps

4 0

3 years ago

Hayden decided to take martial arts classes at his local gym. He pays $35 each month for his membership and $12 for every class

gizmo_the_mogwai [7]

Hayden had the membership for one month and took 6 classes.

8 0

3 years ago

Help me please? c: I only have 4 questions left and I'm a bit stuck

prohojiy [21]

1.168 rounded off to nearest thousands = 1168

6 0

3 years ago

PRECALCULUS please help

sergejj [24]

Answer:

Step-by-step explanation:

$f(x) = \frac{2x + 6}{3x} \\ \\ g(x) = \frac{ \sqrt{x} - 8}{3x}$

To find ( f - g)(x) , subtract g(x) from f(x)

That's

$( f - g)(x) = \frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x}$

Since they have a common denominator that's 3x we can subtract them directly

That's

$\frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x} = \frac{2x + 6 - ( \sqrt{x} - 8) }{3x} \\ = \frac{2x + 6 - \sqrt{x} + 8 }{3x} \\ = \frac{2x - \sqrt{x} + 6 + 8 }{3x}$

We have the final answer as

Hope this helps you

6 0

3 years ago