Answer:
2x2-5x-3
we will take 6's factors that would be the together the sum 5
2x2-6x+1x-3
2x(x-3) +1(x-3)
(2x+1) (x-3)
Answer:
The 32nd term of the arithmetic sequence is -386.
Step-by-step explanation:
Given: The arithmetic sequence where
and
We have to find the 32nd term of the arithmetic sequence.
Consider the given sequence with
and
We know , For a given sequence in an Arithmetic sequence with first term
and common difference d , we have,
![a_n=a_1+(n-1)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%28n-1%29d)
We first find the common difference "d".
, we have,
Solve for d , we have,
-88= 8d
d = - 11
Thus, 32nd term is ![a_{32}=a_1+(32-1)d](https://tex.z-dn.net/?f=a_%7B32%7D%3Da_1%2B%2832-1%29d)
![a_{32}=-34+32\cdot (-11)](https://tex.z-dn.net/?f=a_%7B32%7D%3D-34%2B32%5Ccdot%20%28-11%29)
![a_{32}=-386](https://tex.z-dn.net/?f=a_%7B32%7D%3D-386)
Thus, The 32nd term of the arithmetic sequence is -386.
32-36=-4 So it is 36. Your welcome.
Answer:
Perimeter: 33.7 mm
Area: 54 mm
Step-by-step explanation:
If you do 12 + 9.7 + 12 you will get the perimeter, and to get the area you would use the formula A =
x base x height. Since the base is 12 and the height is 9, you would do 12 x 9 x 0.5 to get 54 mm for the area of the triangle.
To find the area of a square it is 10x10=100 units and to find perimeter it is 10x4=40 units so the area is larger