Answer:
15 is the answer to the question
Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
Y = 250 + 100x....the slope is 100
it represents the per second fee of air time...basically, it costs $ 100 per second for the commercial....wow...100 bucks per second....that radio station is making some money.
Answer:
5/b
Step-by-step explanation:
you would want to add your 1+4 together on top of your b which is your common denominator in this case and you should end up with 5/b
