Answer:
The answer to your question is the letter C
Step-by-step explanation:
Data
sec Ф = 9/2
tan Ф = ?
To solve this problem use trigonometric functions.
1.- The first condition is that the angle must be in the fourth quadrangle
(270° < Ф < 360°).
2.- Write the trigonometric function sec.
sec Ф = hypotenuse / adjacent side and sec Ф = 9/2
then, hypotenuse = 9 adjacent side = 2
3.- Use the Pythagorean theorem to find the adjacent side.
Hypotenuse² = Opposite side² + Adjacent side²
-Solve for Opposite side
Opposite side² = Hypotenuse² - Adjacent side sie²
-Substitution
Opposite side² = 9² - 2²
-Simplification
Opposite side² = 81 - 4
Opposite side² = 77
Opposite side = √77
4.- Find the tan Ф
tan Ф = Opposite side/Adjacent side
-Substitution
tanФ = -√77 / 2 It is negative because in the fourth quadrangle
tan is negative.
You get .4 i believe. you just mulitply the
Average rate = [h(3) - h(0)]/(3 - 0)
h(3) = 300 - 16(3)^2 = 300 - 16(9) = 300 - 144 = 156
h(0) = 300 - 16(0)^2 = 300
average rate = (156 - 300)/3 = -144/3 = -48
Therefore, the object falls with an average rate of 48 ft/s during the first 3 seconds.
40 x 0.08875 = 3.55
40 + 3.55 = 43.55
the sum is $43.55
Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
