The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.
Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
True
1/2 (up the hill) - 1/2 (down the hill) = 0
Hello!
To solve algebraic equation, we will need to use the acronym SADMEP.
SADMEP is similar to PEMDAS, but it is strictly used for solving algebraic equations. Expanded, it is subtract, addition, division, multiplication, exponents, and then parentheses.
Looking at SADMEP, we see that subtract/addition comes first, then division/multiplication, and then exponents/parentheses.
In our equation, our goal is to isolate the variable, "x". Since we have two constants, -3 and 11, and -3 is on the side with the variable, we can add -3 to both sides of the equation first.
Therefore, the first operation needed to solve the equation is addition.
The answer is 80 because the answer for all three sides should be 180
Answer:
ummmmm please explain better
Step-by-step explanation:
