3 years ago

How can I work this out or solve this?

Mathematics

1 answer:

Ede4ka [16]3 years ago

7 0

Add it all up, the answer would be B. 2.37

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Which is a reasonable domain for the function f(x)=10x+8

Soloha48 [4]

Answer:

(-∞,∞)

Step-by-step explanation:

The domain is all possible x values of the function

There are no constraints or holes for this and therefore the domain is all real numbers

8 0

3 years ago

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puteri [66]

Answer: I believe it's 6 5/8

Step-by-step explanation:

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3 years ago

14 + 2(x – 3) = 4(x + 4)

strojnjashka [21]

Answer:

x= -4

Step-by-step explanation:

distribute

combine like terms

subtract 4x from both sides

subtract 8 from both sides

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3 years ago

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Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

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3 years ago

What is pie^2<br><br>________________________________________

mrs_skeptik [129]

Pi^2 = 9.86960440109

8 0

3 years ago

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