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2 years ago

Please help me with the top one please

Mathematics

1 answer:

likoan [24]2 years ago

5 0

Answer:

Ramiro is correct.

You cannot identify congruent triangles with only angles Angle-Angle-Angle is not one of the rules of congruence. They could have different sizes with the same angles which doesn't makes them congruent. They are similar though. Once you find the missing angles with the equations 62+39+C=180 and 39+79+X=180 the corresponding angles are congruent. So the triangles are not congruent, but are similar.

You might be interested in

Which formula is easier to use. Finding the area of a trapezoid or circle? Explain in detail with a minimum of 4 sentence

Scrat [10]

Answer: Circle, in my opinion

Step-by-step explanation:

Trapezoid Formula: (a+b/2)h

Circle Formula: πr*2

Solving a circle requires less steps than solving for a trapezoid would, so in my opinion, finding the area of a circle is easier than a trapezoid.

Hope this helps!

8 0

2 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

2 years ago

PLEASE HELP ME SEE IF MY ANSWERS ARE CORRECT!!!!!!!

Lena [83]

So first one
'how many solutions does 2x-y=-5 and 2x+y=5 have?'
add and get
2x-y-5
plus
2x+y=5

equals
2x+2x+y-y=5-5
4x=0
x=0 always
solve for y
4(0)+y=5
y=5
the solution is (0,5)
only <u>ONE </u>solution

one way is to subsitute
just remember that it is in (x,y) form so
the pont (1,2) means that 1 solution is x=1 and y=2 so subsitute and find that
the first one is the answer you are correct

just look at the graph
the solution is the intersection
it seems to be at a point that is 3 units to the right and -6 units up (6 units down)
so the solution is (3,-6)
yo are corect

subsitution
y=y
therefor
the answe ris (-4,-14) if you did the math correctly

#8 is correct

# 9 is correct

# 10 the answe ris bananas=0.40 pears=0.60

the last one you got it wrong, remember to check your answer to the graph for commonsense
then answer is (-2,5) and (1,2)

8 0

3 years ago

List the first four terms of the geometric sequence.

luda_lava [24]

Answer:

you dont have to say nothing

Step-by-step explanation:

your dum anyways u cant even do nothing right u just on brainly to chet cant do school work and that u are going to fail so sad

3 0

2 years ago

Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized

Roman55 [17]