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natta225 [31]
3 years ago
11

Which the following is a linear algebraic expressionpleaseee...help me in math​

Mathematics
1 answer:
Serga [27]3 years ago
3 0

Answer:

C 9s-8t

Step-by-step explanation:

A linear expression is an algebraic expression in which each term is either a constant or the product of a constant and (the first power of) a single variable. Linear expression can have one or more variables.

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Answer:

both the first one

Step-by-step explanation:

use unit rate

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Find the area of the rectangle ABCD. I need both green and grey box please.
Kitty [74]

Answer:

180

Step-by-step explanation:

12x15=180

5 0
3 years ago
Read 2 more answers
The first blanks options are -2 , -1/2 , 2 , 1/2
Pie

Answer:

equation 1

y = -2x

equation 2

y = x-3

Solution to both

(1,-2)

Step-by-step explanation:

We need to get the equations of both lines

General form is;

y = mx + c

where m is slope and c is the y-intercept

Table 1

since we have a point 0,0; the y-intercept here is zero

Let us get the slope. We can do this by selecting any two points

m = (y2-y1)/(x2-x1)

m = (2-10)/(-1+5) = -8/4 = -2

So the equation of the first line is;

y = -2x

Table 2

we get the slope

m = (4+2)/(7-1) = 6/6 = 1

The partial equation is;

y = x + c

To get c, we select any two point and substitute

4 = 7 + c

c = 4-7

c = -3

So the equation is;

y = x-3

To get the solution to both systems, we equate the y

-2x = x - 3

-2x-x = -3

-3x = -3

x = -3/-3

x = 1

To get y, we substitute;

recall; y = -2x

y = -2(1)

y = -2

Solution to the system is;

(1,-2)

7 0
3 years ago
3/12 1/6 and 1/3 same denominator
iogann1982 [59]
Yes because if you turn 6 and three to 12 then you have 2/12 and 4/12!
5 0
4 years ago
For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

f(x) = x^2;\ k (x) = x ^ 2 -7

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

3 0
3 years ago
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