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GaryK [48]
3 years ago
6

Linda purchases 4/5 of a pound of apples for $5.00. What is the cost per pound of apples?

Mathematics
1 answer:
bonufazy [111]3 years ago
7 0

Answer:

$6.25 per pound

Step-by-step explanation:

We can set up a simple ratio to solve this.

If 4/5 pounds = $5, then 1 pound = x

We can write two ratios and equate them:

\frac{\frac{4}{5}}{5}=\frac{1}{x}\\\frac{4}{5}x=5\\x=\frac{5}{\frac{4}{5}}\\x=5*\frac{5}{4}\\x=\frac{25}{4}\\x=6.25

So 1 pound of apple cost $6.25

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Maksim231197 [3]
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6. Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UND
Darya [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

6a

    V(3) =  113.112

6b

     V(\frac{3}{2})  = 14.139

6c

   V(2r) =  33.514r^3

7a

  h(5) = 0

7b

    h(t) = -5.76

7c

h(x+5) = x(x+5)

Step-by-step explanation:

Considering the question 6

The function given is V(r) =  \frac{4}{3} \pi r^3

For  V(3) we have  

        V(3) =  \frac{4}{3} \pi 3^3

       V(3) =  \frac{4}{3} * 3.142 * 3^3

       V(3) =  113.112

For  V(\frac{3}{2})

        V(\frac{3}{2})  =  \frac{4}{3} *  \pi *   (\frac{3}{2})^3

        V(\frac{3}{2})  =  \frac{4}{3} * 3.142 *   (\frac{3}{2})^3

        V(\frac{3}{2})  = 14.139

For   V(2r)

            V(2r) =  \frac{4}{3} \pi (2r)^3

           V(2r) =  \frac{4}{3} * 3.142*8r^3

           V(2r) =  33.514r^3

Considering the question 7

     The function given is  h(t) = t^2 - 5t

For  h(5)

          h(5) = 5^2 - 5(5)    

           h(5) = 0  

For  h(1.8)

            h(t) = 1.8^2 - 5(1.8)

            h(t) = -5.76

For  h(x+ 5)

              h(x+5) = (x+5)^2 - 5(x+5)

               h(x+5) = x^2 + 25+10x-5x-25

             h(x+5) = x(x+5)

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3 years ago
PLS HELP! <br><br> - x + 4y = -9<br><br> y = -2x + 6<br><br> Is (2,3) a solution of the system?
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Answer is no!!!
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