-3x - 4y - 2z = 0
x + 3y + 2z = 1
-2x - y = 1
-4x - 4y - 2z = 10
3x + 4y +2z= 0
-x = 10. x = -10
-2(-10) - y = 1
20 - y = 1
-y = -19
y = 19
-10 + 3(19) + 2z = 1
-10 + 57 + 2z = 1
47 + 2z = 1
2z = -46
z= -23
check: 2(-10)+2(19)-23=-5
-20+38-23=-5
-43+38=-5
-5=-5
Answer:
6 feet
Step-by-step explanation:
Consider the right triangle formed by the wall, ladder and ground.
Let the distance the ladder is from the wall be d , then
Using Pythagoras' identity in the right triangle
The square on the hypotenuse ( ladder) is equal to the sum of the squares on the other 2 sides ( wall and d ), then
d² + 8² = 10²
d² + 64 = 100 ( subtract 64 from both sides )
d² = 36 ( take the square root of both sides )
d =
= 6
That is the ladder is 6 feet away from the wall
Ok so to find this we need to find 25% of 8 and then add that number to 8 itself. SO .25*8=2. So 2+8=10. So the answer is 10. IF you don't get it just ask and i can try to re explain
<span>y = kx find k
21 = k*3
k = 7
Equation:
y = 7x
Find x when y = 42
42 = 7x
x = 42/7
x = 6
answer: </span><span>x = 6 when y = 42</span>
Answer:
x = ± 5
Step-by-step explanation:
Given
x² - 4x - 25 = - 4x ( add 4x to both sides )
x² - 25 = 0 ( add 25 to both sides )
x² = 25 ( take the square root of both sides )
x = ±
= ± 5