Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
He spent 26.95 on each. It's just 80.85/3 =26.95
Answer:
73.6
Step-by-step explanation:
64x15%=9.6
9.6+64=73.6
Given problem is -4.2y+2.1>-2.52.
To solve this, we combine numbers by transposing -2.52 to the left side and transposing variable term in the right side as shown below:
2.1+2.52>4.2y
Perform addition of values 2.1 and 2.52,
4.62>4.2y
Then, divide both sides with 4.2 and the result is 1.1>y.
The answer is y<1.1.
