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I am Lyosha [343]
3 years ago
10

Red ink pens are sold at $1.50 each black ink pens are sold at $30 which color is the cheaper buy?

Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

Red Ink pens.

Step-by-step explanation:

Red ink pens are sold at $1.50 while Black ink pens are sold at $30. One black ink pens cost more than one red ink pen by $28.50.

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If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
3 years ago
-11=a+7 dolce equation
zubka84 [21]

-11 = a + 7   Given

-7        -7    Subtract 7 on each side to cancel out +7 and isolate variable

-18 = a       Answer

Prove.

-11 = -18 + 7    Plug in variable value

-11 = -11

True.

4 0
3 years ago
Read 2 more answers
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
The sum of Alex's height and Ben's height is 130 inches. Subtracting Alex's height from Ben's height yields one-third of Ben's h
In-s [12.5K]

Ben is 97.5 inches tall.

Alex is 32.5 inches tall.

5 0
3 years ago
Read 2 more answers
What is 12-9×3×4+3 in three different ways
Maurinko [17]
1. 12-9×3×4+3=-93
2.3+4×3×9-12=99
3. 12-9+3×9×3×4=327
4 0
3 years ago
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