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aleksandrvk [35]
3 years ago
12

100,000+4,000+800+5100, comma, 000, plus, 4, comma, 000, plus, 800, plus, 5 in standard form.

Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer: 109,900,000+4,000+800+5

Step-by-step explanation:

First, let’s add the first four numbers: 100,000 + 4,000 + 800 + 5,100. It equals to 109,900.

Next, after we write 109,900;we write a comma. It’ll look like this: 109,900,

Then, we add 000 after the comma. It is going to be like this: 109,900,000

After that, we add a plus sign: 109,900,000+. We still need to add the 4 and the comma: 109,900,000+4,

Then, we add 000, plus, and 800: 109,900,000+4,000+800. It’ll look like that.

Finally, we need to add the plus and the number 5 to the long equation. It’ll look like this:109,900,000+4,000+800+5.

You’re all done! A little tip is to go in order and not do in whatever order.

Anyways, hope this helped!

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Answer:D.

-4°F

Step-by-step explanation:

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3 years ago
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Find the area of each figure. Round to the nearest tenth if necessary.
natita [175]

Answer:

Solution given:

1.

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

  • base*height+½π(d/2)²
  • 8*5+½*π×(6/2)²
  • 40+14.14
  • 54.4mm²
  • <u>Area</u><u> </u><u>:</u><u>5</u><u>4</u><u>.</u><u>1</u><u>4</u><u>m</u><u>m</u><u>²</u>

2.

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

  • =l²+½*b*h
  • =9²+½*6*9
  • =81+27
  • =108ft²
  • <u>Area</u><u>:</u><u> </u><u>1</u><u>0</u><u>8</u><u>f</u><u>t</u><u>²</u>
6 0
3 years ago
Write an equation of the perpendicular bisector of the segment with end points M(1,5) and N(7,-1)
vitfil [10]
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

P=\dfrac{(1,5)+(7,-1)}{2}=\dfrac{(8,4)}{2}=(4,2)

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:

m_r=\dfrac{\Delta y}{\Delta x}=\dfrac{5-(-1)}{1-7}=\dfrac{6}{-6}\iff m_r=-1


p\perp r\Longrightarrow m_p\cdot m_r=-1\Longrightarrow m_p\cdot(-1)=-1\iff m_p=1

We can calculate the equation of p by using its slope and its point P:

y-y_P=m_p(x-x_P)\\\\&#10;y-2=1\cdot(x-4)\\\\&#10;y-2=x-4\\\\&#10;\boxed{p:~~y=x-2}
4 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
4 years ago
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Ludmilka [50]
Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
\left \{ {{x=2y} \atop {10x+y-(10y+x)=36}} \right. \ =\ \textgreater \  \  \left \{ {{x=8} \atop {y=4}} \right.
Check: the original number is 84, the new number is 48; difference is 84-48=36.

answer: 84
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