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3 years ago

Given f(x)=-8x+1 find f(5)

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

7 0

So you plug in 5 for x
-8(5)+1=f(x)
-40+1
-39=f(x)

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Find the sum or different 11/18-1/6

ira [324]

Answer:

4/9

Step-by-step explanation:

11/18-1/6

The first step is to get a common denominator, which is 18. We can multiply 1/6 by 3/3 to get the denominator to 18

11/18 - 1/6 *3/3

11/18 - 3/18

8/18

Now we can simplify the fraction by dividing the top and bottom by 2

4/9

7 0

3 years ago

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The graphic below shows a protractor, which is used to measure angles . What is the level of accuracy of the measurement tool ?

Oksanka [162]

Answer:

Pretty...accurate

Step-by-step explanation:

It's pretty accurate

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3 years ago

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Help I need to turn this in today:)

GalinKa [24]

Total surface area

=2 ×(area of triangle) +( area of rectangle 1) + (area of rectangle 2) + (area of rectangle 3)

2×(1/2 × 16 ×12) + (10×12)+(16×10)+(20×10)

=672 cm²

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3 years ago

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex

natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

Finding the curl of F.

Given $F(x,y,z) = < yz, 4xz, e^{xy} >$ we have:

$curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|$

Working with the determinant we get

$curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k$

Working with the partial derivatives

$curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k$

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS$

where the normal to the circle is just $\hat n= \hat k$ since the normal is perpendicular to it, so we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS$

Only the z-component will not be 0 after that dot product we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3z dS$

Since the circle is at z = 3 we can just write

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3(3) dS\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 9\int \int_S dS$

Thus the integral represents the area of a circle, the given circle $x^2+y^2 = 9$ has a radius r = 3, so its area is $A = \pi r^2 = 9\pi$ , so we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = 9(9\pi)\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 81 \pi$

Thus the result of the integral is 81π

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3 years ago

The expression below is the factorization of what trinomial? (7x + 5)(2x - 3)

allsm [11]

You can simply expand the factorised form out:
y = 14x² - 21x + 10x - 15
y = 14x² -11x -15

8 0

3 years ago

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