Answer: 2 m/s
Step-by-step explanation:
The position time graph shown above has position or distance on the vertical axis and time on the horizontal axis. The unit of the distance is in metes and the unit of the time is in seconds.
Distance = velocity / time
Time = distance × time
From the graph, the slope at any point determines the velocity of the object at that point.
Slope =( y2 -y1)/ ( x2 -x1)
y2 = 5(corresponding to the point on the vertical axis where t = 2.5 on the horizontal meets the plotted line when traced along the vertical axis)
y 1 = 0 (initial distance)
x2 = 2.5( on the horizontal axis)
x1 = 0(initial time)
Velocity = slope = (5-0)/2.5-0)= 5/2.5
= 2 m/s
To do this we need to rearrange the equation.
m = -8j - 9k + 9
Subtract (-8j + 9) from both sides
m + 8j - 9 = -9k
Divide both sides by -9
(m + 8j - 9)/-9 = k
The answer is C
Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
