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Ann [662]
3 years ago
9

Two automobiles left simultaneously from cities A and B heading towards each other and met in 5 hours. The speed of the automobi

le that left city A was 10 km/hour less than the speed of the other automobile. If the first automobile had left city A 4.5 hours earlier than the other automobile left city B, then the two would have met 150 km away from B. Find the distance between A and B. THE ANSWER IS NOT 1600 KM!!!!!!!!!
Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

Answer: 1600  Km

Step-by-step explanation: yes it is.

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Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

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The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
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  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
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Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

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