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Ann [662]
4 years ago
9

Two automobiles left simultaneously from cities A and B heading towards each other and met in 5 hours. The speed of the automobi

le that left city A was 10 km/hour less than the speed of the other automobile. If the first automobile had left city A 4.5 hours earlier than the other automobile left city B, then the two would have met 150 km away from B. Find the distance between A and B. THE ANSWER IS NOT 1600 KM!!!!!!!!!
Mathematics
1 answer:
hodyreva [135]4 years ago
4 0

Answer: 1600  Km

Step-by-step explanation: yes it is.

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Step-by-step explanation:

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Explanation:

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Factor these out by dividing each term by the GCF of each group.

\begin{gathered} =5a(\frac{10a^2}{5a}-\frac{5ab}{5a})+4c(\frac{8ac}{4c}-\frac{4bc}{4c}) \\  \\ =5a(2a-b)+4c(2a-b) \end{gathered}

Since the terms inside the brackets are the same, combine:

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CHECK

To check if your result is correct in cases like these, expand as follows:

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Answer:

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