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rewona [7]
2 years ago
11

Which are the roots of the quadratic function f(g) = 92 – 125? Select two options.

Mathematics
1 answer:
kolezko [41]2 years ago
6 0

Answer:q=575

Step-by-step explanation:

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Verify the identity
Thepotemich [5.8K]

<u>Given</u>:

Given that we need to prove the identity \sin x+\sin x \tan ^{2} x=\tan x \sec x

<u>Proof</u>:

Step 1: Factor out the common term sin x, we get;

\sin x\left(1+\tan ^{2} x\right)=tan \ x \ sec \ x

Step 2: Using the identity 1+tan^2 x=sec^2x

\sin x \sec ^{2} x=tan \ x \ sec \ x

Step 3: Reciprocating sec x, we get;

\sin x \cdot \frac{1}{\cos ^{2} x}=tan \ x \ sec \ x

Step 4: Splitting the denominator, we have;

\frac{\sin x}{\cos x} \cdot \frac{1}{\cos x}=tan \ x \ sec \ x

Simplifying, we get;

\tan x \sec x=\tan x \sec x

Thus, the identity is proved.

5 0
3 years ago
I need help please.
erica [24]
Answer is #3
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5 0
3 years ago
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Plz helpp. In a high school with 5,000 students, the number of text messages sent by each student during a particular month was
vampirchik [111]

Answer:

A) 800

Step-by-step explanation:

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8 0
3 years ago
Mara works in a music store and has a guitar on sale for 35% off. The guitars regular price is $630, what is the sale price?
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3 0
2 years ago
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


8 0
2 years ago
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