Answer:
D -$7.20
Step-by-step explanation:
- If she takes (substance) $2.40 every times she forgets to do a chores you have to substance
- but first you have to multiply because she forgets 3 times
- 2.40 × 3 is 7.20
- but since she taking it away it would be negative
so your answer is -$7.20
I hope this helps
Answer:
-3/2.
Step-by-step explanation:
To find the slope, we find the rise over run.
In this case, the rise is 6 - 3 = 3.
The run is 3 - 5 = -2.
The slope is 3 / (-2) = -3/2.
Hope this helps!
Given that the point B is (1,1) is rotate 90° counterclockwise around the origin.
We need to determine the coordinates of the resulting point B'.
<u>Coordinates of the point B':</u>
The general rule to rotate the point 90° counterclockwise around the origin is given by

The new coordinate can be determined by interchanging the coordinates of x and y and changing the sign of y.
Now, we shall determine the coordinates of the point B' by substituting (1,1) in the general rule.
Thus, we have;
Coordinates of B' = 
Thus, the coordinates of the resulting point B' is (-1,1)
Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>
The sum of the inner angles of any triangle is always 180°, i.e. you have

In the particular case of an equilater triangle, all three angles are the same, so

and the expression becomes

which implies 
So, if you rotate the triangle with respect to its center by 60 degrees, the triangle will map into itself. In particular, if you want point A to be mapped into point B, you have to perform a counter clockwise rotation of 60 degrees with respect to the center of the triangle.
Of course, this is equivalent to a clockwise rotation of 120 degrees.
Finally, both solutions admit periodicity: a rotation of 60+k360 degrees has the same effect of a rotation of 60 degrees, and the same goes for the 120 one (actually, this is obvisly true for any rotation!)