
=
1/3 ( because the limit as x approaches 0 of t/sin t = 1 ).
Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic

p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Answer:
The answer is 9996
Step-by-step explanation:
Using the identity (x+a)(x+b) = x ^2 +(a+b)x+ab
Writing 102 as 100+2 and 98 as 100−2
Hence (100+2)(100−2) = 100 ^2 +[2+(−2)]100+(2)(−2)
= 10000+(0)100−4
= 9996
The answer is 9996
Answer:

Step-by-step explanation:
So we have the equation:

First, subtract 3 from both sides:

Definition of absolute value:

Divide both sides by 6 for both equations:

And we're done!